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template <class Rhs, class Ret=dont_care>
struct has_dereference : public true_type-or-false_type {};

Inherits: If (i) rhs of type Rhs can be used in expression *rhs, and (ii) Ret=dont_care or the result of expression *rhs is convertible to Ret then inherits from true_type, otherwise inherits from false_type.

The default behaviour (Ret=dont_care) is to not check for the return value of prefix operator*. If Ret is different from the default dont_care type, the return value is checked to be convertible to Ret. Convertible to Ret means that the return value of the operator can be used as argument to a function expecting Ret:

void f(Ret);
Rhs rhs;
f(*rhs); // is valid if has_dereference<Rhs, Ret>::value==true

If Ret=void, the return type is checked to be exactly void.

Header: #include <boost/type_traits/has_dereference.hpp> or #include <boost/type_traits/has_operator.hpp> or #include <boost/type_traits.hpp>

Compiler Compatibility: Requires working SFINAE (i.e. BOOST_NO_SFINAE is not set). Only a minority of rather old compilers do not support this.


has_dereference<Rhs, Ret>::value_type is the type bool.

has_dereference<Rhs, Ret>::value is a bool integral constant expression.

has_dereference<int*>::value is a bool integral constant expression that evaluates to true.

has_dereference<long*> inherits from true_type.

has_dereference<int*, int> inherits from true_type.

has_dereference<int*, const int> inherits from true_type.

has_dereference<int const *> inherits from true_type.

has_dereference<int * const> inherits from true_type.

has_dereference<int const * const> inherits from true_type.

has_dereference<int> inherits from false_type.

has_dereference<double> inherits from false_type.

has_dereference<void*> inherits from false_type.

has_dereference<const int*, int&> inherits from false_type.

See also: Operator Type Traits

Known issues: